Draw the products of the following reactions: Part A There is a scheme of a reaction between two compounds, which react in the presence of PdL2 and (CH3CH2 )3 N. The first compound consists of CH double bond CH. The first (from left to right) carbon has a CH3 group attached above the plane of the bond. The second carbon has an I atom attached below the plane of the bond. The second compound is a line-angle structure consisting of two carbon atoms in the chain, with a double bond between the carbons and a C triple bond N group attached.

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .