Suppose you heat a metal object with a mass of 31.7 g to 96.5 oC and transfer it to a calorimeter containing 100.0 g of water at 17.3 oC. The water and metal reach a final temperature of 24.6 oC. What is the specific heat of the metal in J/g-oC?

The specific heat of the metal in

Explanation:

As we know that,  

where,

= mass of metal = 31.7 g

= mass of water = 100.0 g

= final temperature =

= temperature of metal =

= temperature of water =

= specific heat of metal= ?

= specific heat of water =  

Now put all the given values in equation (1), we get

Therefore, the specific heat of the metal in

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.