Someone help me pls thank you

The solubilty product (Ksp) of PbCl₂ : Ksp = [Pb²⁺][Cl⁻]²

Given

PbCl₂ compound

Required

The solubilty product (Ksp)

Solution

Ksp is the product of ions in an equilibrium saturated state

For reaction :

AₓBₐ (s) ⇔ aAᵃ⁺ (aq) + b Bᵇ⁻ (aq)  

Can be formulated :

Ksp = [Aᵃ⁺] ᵃ [Bᵇ⁻] ᵇ  

For PbCl₂ :

PbCl₂(s)⇔Pb²⁺(aq) + 2Cl⁻(aq)

Ksp = [Pb²⁺][Cl⁻]²

i think it's letter a.