At what temperature will 7.2 moles of a gas under 107.5 kPa of pressure that takes up 748 cm^3 be?

The temperature = T = 1.29 K

Given

n = 7.5 moles

P = 107.5 kPa = 1,0609425 atm

V = 748 cm³ = 0.748 L

Required

Temperature

Solution

Ideal gas law :

PV = nRT

T = (PV)/(nR)

T = (1,0609425 x 0.748)/(7.5 x 0.08205)

T = 1.29 K

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

2b2t

explanation:

2b2t