How many grams is 5.4x10 to the 23 molecules of al2o3?

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72