6. (10 Points) The volume of a helium balloon in Los Angeles is 14.0 L The temperature in Los Angeles is 25°C. Find the volume of the balloon in
Death Values where the temperature is 52°C, with the pressure being the
same in both places.
PLS HURRY

V₂ = 15.27 L

Explanation:

Given data:

Initial volume = 14.0 L

Initial temperature = 25°C (25 + 273.15 = 298.15 k)

Final temperature = 52°C = (52+273.15 = 325.15 k)

Final volume = ?

Solution:

Charles Law:

" The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure "

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 14.0 L × 325.15 K / 298.15 k

V₂ = 4552.1 L.K / 298.15 K

V₂ = 15.27 L

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."