b
. 0.351 L.
Explanation:
Hello!
In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:
![C_1V_1=C_2V_2](/tpl/images/1068/9083/4b2d0.png)
Thus, solving for the volume of the stock solution, V1, we obtain:
![V_1=\frac{C_2V_2}{C_1}](/tpl/images/1068/9083/ef64e.png)
Now, by plugging in the given data we obtain:
![V_1=\frac{1.2M*0.585L}{2.0M}\\\\V_1=0.351L](/tpl/images/1068/9083/26a06.png)
Therefore, the answer is b
. 0.351 L.
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