What is the maximum mass of ammonia (NH3) that can be produced from the synthesis reaction of 781 g of nitrogen and 656 g hydrogen? HINT: You will need to write a balanced chemical equation and perform 2 calculations before you can determine the answers.

N2(g)+3H2 >>>>>2NH3(g)

the mole ratio between N2, H2 and NH3. It is 1 : 3 : 2

mole N2 present
moles H2 present = 25.0 g H2 x 1 mole H2/2 g = 12.5 moles H2 present
Based on mole ratio, N2 is limiting in this situation because there is more than enough H2 but not enough N2.

moles NH3 that can be produced = 1 mole N2 x 2 moles NH3/mole N2 = 2 moles NH3 can be produced
grams of NH3 that can be produced = 2 moles NH3 x 17 g/mole = 34 grams of NH3 can be produced

Sorry i dont understand the question can you rephase it?