Which of the following transitions (in a hydrogen atom) represent emission of the longest wavelength photon?
a) n = 1 to n = 2
b) n = 3 to n = 1
c) n = 3 to n = 4
d) n = 4 to n = 2
e) n = 5 to n = 4

E) n = 5 to n = 4

Explanation:

Since the question stated that it is an emission process, options involving increase in transitions are to be ignored. This means option a and b are to be ignored as they refer to absorption.

We are left with three options.

The second option can be dropped because of the huge energy gap involved. Any drop into level one is in the ultraviolet, which are short wavelengths.

We are left with two options now.

The fouth is a transition between two levels, ehich means extra energy involved.

The fifth is a transition between just one level, which means lesser energy is involed.

Energy and wavelength are inversely proportional to each other, so the higher the energy, the lesser the wavelenth.

The emission with the longest wavelength (or, least energy) is the last option, the 5 to 4 transition.

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nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.