Several balloons are inflated with helium to a volume of 0.75 L at 27°C. One of the balloons was found several hours later, the temperature had dropped to 22°C. What would be the volume of the balloon when found, if no
helium has escaped? (0.74L)

V₂ = 0.74 L

Explanation:

Given data:

Initial volume of balloon = 0.75 L

Initial temperature of balloon = 27°C (27+273.15 K = 300.15 K)

Final volume of balloon = ?

Final temperature = 22°C (22+273.15 K = 295.15 k)

Solution:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 0.75 L × 295.15 k / 300.15 K

V₂ = 221.36 L.K / 300.15 K

V₂ = 0.74 L

The given problem is solved through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂