How many atoms of aluminum (Al) are in 2.34 mol of aluminum?

 " " atoms of aluminum (Al) .

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Explanation:

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Using a technique called "dimensional analysis" ; as follows:

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→  "  

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The units "mol Al" ["moles of aluminum"] cancel out; and we have:

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→  " atoms of Al [aluminum].

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Note that by definition: 1 (one) "mole" (abbreviated "mol") of anything consists of " " units " of that particular thing.

 This number:  6.022*10^{23} —is known as:  "Avogadro's number".

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→  [ 2.34 * 6.022 * 10^23] ;

     = 1.409148 * 10^24 ;

                → Round to 3 (Three) significant figures;

                →  since: "2.34" has 3 (Three) significant figures;

                  →  to get: "  atoms of aluminum (Al).

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Hope this is helpful to you!  Wishing you the best!

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