Acompound is decomposed in the laboratory and produces 1.40 g n and 0.20g h what is the empirical formula

First, find the number of moles for each element. The molar mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.

1.40 g N / 14 g/mol = 0.1 mol N

0.20 g H / 1 g/mol = 0.2 mol H

Find the mole ratio. Divide both numbers with the much lower value. In this case, it is 0.1 mol N.

For N: 0.1 ÷ 0.1 = 1

For H: 0.2÷0.1 = 2

Thus, the empirical formula is .

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.