How many grams is 26.17 L Xe at STP

Mass = 157.56 g

Explanation:

Given data:

Mass of Xe in gram = ?

Volume = 26.17 L

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Solution:

we will calculate the number of moles first.

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm ×26.17 L = n×0.0821 atm.L/ mol.K  × 273.15 K

26.17 atm.L = n× 22.43 atm.L/ mol

n = 26.17 atm.L / 22.43 atm.L/ mol

n = 1.2 mol

Mass of Xe:

Mass = number of moles × molar mass

Mass = 1.2 mol × 131.3 g/mol

Mass = 157.56 g

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