2Sr(s)+O2(g)→2SrO(s) calculate how many grams of the product form when 16.4 of Sr completely reacts.

Assume that there is more than enough of the other reactant.

Mass = 19.68 g

Explanation:

Given data:

Mass of product formed = ?

Mass of Sr  16.4 g

Solution:

Chemical equation:

2Sr + O₂      →    2SrO

Number of moles of Sr:

Number of moles = mass /molar mass

Number of moles = 16.4 g/ 87.62 g/mol

Number of moles = 0.19 mol

Now we will compare the moles of Sr with SrO.

                     Sr           :         SrO

                      2           :           2

                    0.19        :         0.19

Mass of Sr:

Mass = number of moles × molar mass

Mass = 0.19 mol × 103.62 g/mol

Mass = 19.68 g

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).