Calculate the volume in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid. Show your work and give your answer to the correct number of significant figures.

4.8 mL of 1.043 M acetic acid that is needed to prepare 50.0 mL of 0.10 M acetic acid

Explanation:

According to the dilution law,

where,

= molarity of stock solution = 1.043 M

= volume of  stock solution = ?

= molarity of diluted solution = 0.10 M

= volume of diluted solution = 50.0 ml

Putting in the values we get:

Therefore, volume  in mL of 1.043 M acetic acid (CH3COOH) that is needed to prepare 50.0 mL of 0.10 M acetic acid is 4.8

3 1/4 %

explanation: