A 5.5 kg rifle fires an 11 g bullet with a velocity of 1000 m/s. (a) What is the recoil velocity of the rifle? (b) If the shooter holds the rifle firmly against his shoulder, What will be the recoil velocity? Assume the mass of the shooter is 120 kg. Please answer seriously (;´༎ຶٹ༎ຶ`)

Given,

Mass of a rifle = 5.5 kg

Mass of a bullet = 11 g

Speed of a bullet = 1000 m/s

To find,

(a) The recoil velocity of the rifle.

(b) If the shooter holds the rifle firmly against his shoulder, What will be the recoil velocity.

Solution,

(a) Let v₁ is the recoil velocity of the rifle. We can use the conservation of momentum to find it. The momentum of the system will remains conserved.

So, the recoil velocity of the rifle is 2 m/s and it is in opposite direction of he bullet.

(b) Let V is the recoil velocity if the shooter holds the rifle firmly against his shoulder. Again using the conservation of momentum.

Therefore, this is the required solution.

the answer is a. co2, this would be colder than the : )

explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)