Assuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.

The mole fraction of oxygen gas : 0.381

Given

2.31 atm Oxygen

3.75 atm Hydrogen

Required

The mole fraction of Oxygen

Solution

Dalton Law's of partial pressure

P tot = P₁ + P₂ + ..Pₙ

Input the value :

P tot = P O₂ + P H₂

P tot = 2.31 atm + 3.75 atm

P tot = 6.06 atm

The mole fraction of O₂ (X O₂):

P O₂ = X O₂ x P tot

X O₂ = P O₂ / P tot

X O₂ = 2.31 /6.06

X O₂ = 0.381

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