A sample of oxygen occupies a volume of 150 cm3 at 72 C. What will be volume of oxygen when the temperature drops to 2 C?

V₂ = 119.59 cm³

Explanation:

Given data:

Initial volume = 150 cm³

Initial temperature = 72°C

Final volume = ?

Final temperature = 2°C

Solution:

Initial temperature = 72°C (72 +273.15 K = 345.15 K)

Final temperature = 2°C (2 + 273.15 k = 275.15 K)

Solution:

According to the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 150 cm³ × 275.15 K /345.15 K

V₂ = 41272.5 cm³.K / 298 K

V₂ = 119.59 cm³

qualitative observation deals with data that can be observed with our senses: sight, smell, touch, taste, and hearing. they do not involve measurements or numbers. for instance, colors, shapes, and textures of objects are all qualitative observations.

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.