A 10.0 g sample of water was heated from 20.0°C to 50.0°C. How much energy did the water gain? The specific heat of water is 4.18 J/g·°C. 836 J 836 J 1250 J 1250 J 2920 J 2920 J 4180 J

1254 J

Explanation:

Mass, m = 10.0g

Initial Temperature = 20°C

Final Temperature = 50°C

Energy = ?

Specific heat capacity, c = 4.18 J/g·°C

The relationship between these quantities is given by the equation;

H = mcΔT

ΔT = Final Temperature - Initial Temperature = 50 - 20  = 30 °C

H = 10 * 4.18 * 30

H = 1254 J