Can someone show me the work on 3-8?

3. 426 g

4.  413.4 g

5. 1328.4 g

6. 192.4 g

7. 106.4 g

8. 0.617 mol

Given

moles and mass

Required

Conversion mole to gram

Solution

General formula :

mole (n) = mass : MW

3. 6 moles Cl₂(MW = 71 g/mol) :

= 6 moles x 71 g/mol

= 426 g

4. 5.3 moles CaF₂(MW=78 g/mol)

= 5.3 mol x 78 g/mol

= 413.4 g

5. 8.2 moles FeCl₃(MW=162 g/mol)

= 8.2 mol x 162

= 1328.4 g

6. 2.6 moles Li₂CO₃(MW=74 g/mol)

= 2.6 mol x 74 g/mol

= 192.4 g

7. 3.8 moles N₂(MW=28 g/mol)

= 3.8 mol x 28 g/mol

= 106.4 g

8. 100 g FeCl₃(MW=162 g/mol)

= 100 g : 162 g/mol

= 0.617 mol

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.