What is the ∆G for the following reaction under nonstandard conditions where the following data is given? 2NH4Cl(s) + CaO(s) CaCl2(s)+ H2O + 2NH3(g)

Given:
CaO: ∆Hf = -635.09 kJ, ∆Sf =39.75 J/K
CaCl2: ∆Hf = -795.8 kJ, ∆Sf =104.6 J/K.
NH3: ∆Hf = -46.11 kJ, ∆Sf = 192.45,
H2O: ∆Hf = -285.830 kJ, ∆Sf = 69.91 ,
NH4Cl: ∆Hf = -314.43 kJ, ∆Sf = 94.6
A.
2.27 J
B.
-4.54 J
C.
4.54 J
D.
9.08 J
E.
-9.08 J

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

can you list the answers so i can answer

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.