How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)

0.113 moles of NaCl are created as a result of decomposing 12 grams of .

Explanation:

To calculate the moles :

The balanced chemical equation for decomposition of is:

According to stoichiometry :

2 moles of give = 2 moles of

Thus 0.113 moles of give =  of

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of .

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

it takes on an electronical energy