A balloon is inflated to a volume of 1.25L .If the temperature of the air inside is cooled from 35°C to 15°C , what will be the final volume of the balloon?

V₂ = 1.17 L

Explanation:

Given data:

Initial volume of balloon = 1.25 L

Initial temperature = 35°C

Final temperature = 15°C

Final volume = ?

Solution:

Initial temperature = 35°C (35+273.15K = 308.15 K)

Final temperature = 15°C (15+273.15 K = 288.15 K)

The given problem will be solve through the Charles Law.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.25 L × 288.15 K / 308.15 k

V₂ = 360.2  L.K / 308.15 k

V₂ = 1.17 L

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