si tengo 45 litros de helio en un globo a 250 C y aumento la temperatura del globo a 550 C, ¿Cuál será el nuevo volumen del globo?

Respuesta:

71 L

Explicación:

Paso 1: Información dada

Paso 2: Convertir las temperaturas a Kelvin

Para trabajar con gases necesitamos considerar las temperaturas absolutas. Podemos covertir de Celsius a Kelvin usando la siguiente fórmula.

K = °C + 273.15

K = 250°C + 273.15 = 523 K

K = 550°C + 273.15 = 823 K

Paso 3: Calcular el volumen final

Para un gas ideal que experimenta un cambio a presión constante, podemos calcular el volume final usando la Ley de Charles.

V₁/T₁ = V₂/T₂

V₂ = V₁ × T₂/T₁

V₂ = 45 L × 823 K/523 K = 71 L

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j