FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl How many grams of NaCl could you make with 2.43306 g of FeCl3?

g NaCl (use 5 sig figs

2.6299 g NaCl

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Stoichiometry

Step 1: Define

[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

[Given] 2.43306 g FeCl₃

Step 2: Identify Conversions

[RxN] 1 mol FeCl₃ = 3 mol NaCl

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na - 22.99 g/mol

Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We need 5 sig figs (instructed).

2.62986 g NaCl ≈ 2.6299 g NaCl

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.