4 NH3 + 5 O2 - 4 NO + 6 H20 Given 20 moles of O2 and 14 moles of NH3, which would act as the limiting reactant?

NH₃ as the limiting reactant

Given

Reaction

4 NH3 + 5 O2 ⇒ 4 NO + 6 H20

Required

The limiting reactant

Solution

To find the limiting of the reactants, we can use the method by dividing the moles of each reactant by the reaction coefficient. The smallest ratio will be the limiting reactants

the mol ratio of NH₃ : O₂ =

=14/4 : 20/5

= 3.5 : 4

So NH₃ as the limiting reactant

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying

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