Consider the following reaction sequence. E+S kk1→kk2←(ES)1 kk3→kk4←(ES)2 kk5→E+P Derive suitable expressions for product formation, v, by using: (a) the rapid equilibrium approach, and (b) the quasi-steady-state approach. Your final expressions for parts a and b should only contain reaction rate constants (k1,k2,k3,k4,and k5) and the concentrations [S] and [E0].

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72

idk what is it? is this a question that you know the answer or u dont