Calculate the number of carbon hydrogen and oxygen atoms in 1.5 gram of glucose

The number of atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Given

1.5 g glucose(C₆H₁₂O₆)

Required

The number of atoms

Solution

mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :

mol = mass : MW

mol = 1.5 : 180

mol = 0.0083

Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹

There are 6 C, 12 H and 6 O, so number or atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous