My teacher gives me a block of some unknown material. I weigh it and find out that it weighs 22.5g. I then heat it up using 2067J of energy and notice that it only changes by 25 degrees celsius. What is its specific heat?

The specific heat of unknown material : 3.675 J/g °C

Given

mass of block = 22.5 g

Q = heat = 2067 J

Δt=25 °C

Required

The specific heat

Solution

Heat can be formulated :

Q = m.c.Δt

Input the value :

2067 J = 22.5 g x c x 25 °C

c = 3.675 J/g °C

it is important to conserve water because there is very limited amount of freshwater here on earth and if we are not smart about how we use it we will only be runnning out of our supply faster than neccessarry.

2b2t

explanation:

2b2t