Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. Suppose 4.05 g of hydrobromic acid is mixed with 2.6 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

.70 g of water will be formed.

Explanation:

NaOH    +   HBr  =   NaBr  +  H₂O

 40 g        103 g                    18 g

40 g of sodium hydroxide reacts with 103 g of HBr

2.6 g of sodium hydroxide reacts with 103 x 2.6 / 40 = 6.7 g of HBr

4.05 g of HBr is available so HBr is limiting reagent .

103 g of HBr reacts with  NaOH  to form 18 g of water

4.05  g of HBr  reacts with  NaOH  to form 18 x 4.05  / 103 g

= .70 g of water will be formed.