A 2-lb sample of an unknown liquid occupies a volume of 62.6 in.3 For the liquid determine (a) the specific volume, in ft3 /lb, and (b) the density, in lb/ft3 .

a) 0.018 ft^3

b) 55.55 lb/ft^3

Explanation:

given that mass m = 2 lb

volume = 62.6 in^3

= 0.036 ft^3

now, specific volume  = volume/mass  [specific volume is the reciprocal of density]

=0.036/2 = 0.018 ft^3.

b) density = mass/ volume = 2/0.036 = 55.55 lb/ft^3

for points guys

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