What is the mass of 5.2 x 10^21 atoms of Vanadium?

Mass = 0.44 g

Explanation:

Given data:

Mass of vanadium =  ?

Number of atoms of vanadium = 5.2 × 10²¹ atoms

Solution:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

5.2 × 10²¹ atoms ×  1mol / 6.022 × 10²³ atoms

0.86× 10⁻²  mol

0.0086 mol

Mass of vanadium:

Mass =  number of moles × molar mass

Mass = 0.0086 mol × 50.9 g/mol

Mass = 0.44 g

im not exactly sure but i think its b!