How many calories of energy are required to heat an 87 g piece of iron from 30*C to 40*C?. ses

(The is the specific heat of iron is 0.110 cal/g x *C)

95.7 cal

Explanation:

The heat required can be calculated as follows:

heat = m x Cp x ΔT

Where:

m = mass of iron = 87 g

Cp = specific heat of iron = 0.110 cal/g.°C

ΔT = change in temperature = final T - initial T = 40°C - 30°C = 10°C

Thus, we introduce the data in the mathematical equation to calculate the heat in calories:

heat = 87 g x 0.110 cal/g.°C x 10°C = 95.7 cal

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