Reaction: 2 Ag2CO3 --> 4 Ag + 2 CO2 + O2, how many moles of silver will be produced when 97.4g of silver carbonate decomposes?

0.7 moles of Ag are produced

Explanation:

Given data:

Mass of silver carbonate = 97.4 g

Moles of silver produced = ?

Solution:

Chemical equation:

2Ag₂CO₃     →     4Ag + 3CO₂

Number of moles of Ag₂CO₃ :

Number of moles = mass/molar mass

Number of moles = 97.4 g/ 275.75 g/mol

Number of moles = 0.35 mol

Now we will compare the moles of Ag and Ag₂CO₃.

              Ag₂CO₃           :         Ag

                    2                :           4

                0.35              :             4/2×0.35 = 0.7

0.7 moles of Ag are produced.