How many moles of Aluminum are produced when34.2 g of alumina are broken down through the process of electrolysis

0.670 mol

Explanation:

Step 1: Write the balanced reaction for the decomposition of alumina

2 Al₂O₃ ⇒ 4 Al + 3 O₂

Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃

The molar mass of Al₂O₃ is 101.96 g/mol.

34.2 g × 1 mol/101.96 g = 0.335 mol

Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃

The molar ratio of Al₂O₃ to Al is 2:4.

0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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