Curicun, named for marie curie, has approximately 25 different isotopes that emit an alpha particle when their nuclei decay. if curium-247, the most abundant nuclide, emit and alpha particle, what daughter nuclide is formed? A. Californium-251
B. Plutonium-243
C. Californium-249
D. Plutonium-251

Option B. Plutonium-243

Explanation:

To know the the correct answer to the question, we shall write the balanced equation for the reaction showing curium-247 (²⁴⁷Cm) emitting alpha particle. This is illustrated below:

²⁴⁷₉₆Cm —> ᵐₙX + ⁴₂He

Next, we shall determine m, n and X. This can be obtained as follow:

247 = m + 4

Collect like terms

247 – 4 = m

243 = m

Thus, m is 243

96 = n + 2

Collect like terms

96 – 2 = n

94 = n

Thus, n is 94

m = 243

n = 94

ᵐₙX => ²⁴³₉₄X => ²⁴³₉₄Pu

Thus, the equation is:

²⁴⁷₉₆Cm —> ²⁴³₉₄Pu + ⁴₂He

From the illustrations above, the daughter nuclei formed is Plutonium-243 (²⁴³₉₄Pu)

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.