How many moles of NaCl are present in 2.50 L of a 0.070 M solution? a

2.8 x 10-2 moles of NaCl

b

35.7 moles of NaCl

c

1.75 x 10-4 moles of NaCl

d

0.175 moles of NaCl

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

So,

Therefore, number of moles of NaCl is 0.175 moles.