A 3.24-gram sample of NaHCO3 was completely decomposed in an experiment. 2NaHCO3 → Na2CO3 + H2CO3

In this experiment, carbon dioxide and water vapors combine to form H2CO3. After decomposition, the Na2CO3 had a mass of 2.19 grams.

Determine the mass of the H2CO3 produced.
Calculate the percentage yield of H2CO3 for the reaction. Show your work or describe the calculation process in detail.

Theoretical Yield = 1.93g H₂CO₃, %yield = 94.3%

Explanation:

Knowing that NaHCO₃ is the only reactant in the equation, it's easily the limiting reactant. Convert the given mass of NaHCO₃ to mass of H₂CO₃ through stoichiometry. The actual given yield of H₂CO₃ is 1.82g, so you just use the percent yield equation.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

the atomic mass is the bottom number on the element.

-steel jelly