S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O How many moles of HNO3 must react to form 14.5 moles of H2O?

43.5 moles of HNO₃.

Explanation:

The balanced equation for the reaction is given below:

S + 6HNO₃ —> H₂SO₄ + 6NO₂ + 2H₂O

From the balanced equation above,

6 moles of HNO₃ reacted to produce 2 moles of H₂O.

Finally, we shall determine the number of mole of HNO₃ required to produce 14.5 moles of H₂O.

This can be obtained as illustrated below:

From the balanced equation above,

6 moles of HNO₃ reacted to produce 2 moles of H₂O.

Therefore, Xmol of HNO₃ will react to produce 14.5 moles of H₂O i.e

Xmol of HNO₃ = (6 × 14.5)/2

Xmol of HNO₃ = 43.5 moles

Therefore, 43.5 moles of HNO₃ is required to produce 14.5 moles of H₂O.

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