What is the molarity of a magnesium chloride solution with 90.5 g of MgCl2 dissolved in a solution with a total volume of 2300 mL?

Molarity = 0.41 M

Explanation:

Given data:

Mass of MgCl₂ = 90.5 g

Volume of solution = 2300 mL (2300/1000 = 2.3 L)

Molarity of solution = ?

Solution:

Number of moles of MgCl₂:

Number of moles = mass/molar mass

Number of moles = 90.5 g/ 95.2 g/mol

Number of moles = 0.95 mol

Molarity:

Molarity = number of  moles / volume in L

Molarity = 0.95 mol / 2.3 L

Molarity = 0.41 M