Methane gas combusts according to the following chemical equation:
CH4 (8) + 202(g) → CO2(g) + 2H2O(l)
29.2 L of methane gas is combusted with 63.3 L of
oxygen gas at STP. What volume of carbon dioxide
is produced in the reaction?
___L CO2
Your answer should be rounded to three significant figures. Do
not include units in your answer.

The volume of carbon dioxide is produced in the reaction is 29.12 L

We know that

1 mol gas at STP = 22.4 L

So,

The mol methane is

Now

The  mol oxygen is

Now the volume is

= 29.12 L

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The volume of Carbon dioxide : 29.12 L

Given

CH4 (g) + 202(g) → CO2(g) + 2H2O(g)

Oxygen volume = 63.3 L

Methane volume = 29.2 L

The volume of Carbon dioxide

Solution

1 mol gas at STP = 22.4 L

mol methane :

mol oxygen :

limiting reactant : CH₄(smaller ratio:mol/reaction coefficient)

So mol CO₂ based on CH₄

From equation, CO₂ : CH₄ = 1 : 1, so mol CO₂ = 1.3

The volume =

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