How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid? H2SO4(aq) + NaOH(aq) = 2H2O(L) + Na2SO4(aq)

Select one:
a. 46.2 moles NaOH
b. 11.6 moles NaOH
c. 5.78 moles NaOH
d. 23.1 moles NaOH

46.2 moles of NaOH are required.

Explanation:

Given data:

Moles of NaOH required = ?

Moles of H₂SO₄ = 23.1 mol

Solution:

Chemical equation:

H₂SO₄ + 2NaOH         →       2H₂O + Na₂SO₄

Now we will compare the moles of NaOH with H₂SO₄.

              H₂SO₄         :            NaOH

                1                :                2

             23.1              :        2×23.1 = 46.2

Thus, 46.2 moles of NaOH are required.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

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