Calculate the volume of a 0.225M solution of KOH required to react with 0.215g of acetic acid.

V = 0.018 L

Explanation:

Given data:

Mass of acetic acid = 0.215 g

Molarity of KOH = 0.225 M

Volume of KOH required = ?

Solution:

Chemical equation:

CH₃COOH + KOH      →    CH₃COOK + H₂O

Number of moles of acetic acid:

Number of moles = mass/molar mass

Number of moles = 0.215 g / 60.0 g/mol

Number of moles = 0.004 mol

now we will compare the moles of acetic acid and KOH.

                          CH₃COOH       :       KOH

                                  1                :          1

                              0.004           :       0.004

Volume of KOH required:

Molarity = number of moles / volume

0.255 M = 0.004 mol / V

V = 0.004 mol / 0.225 mol/L

V = 0.018 L

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

answer : a model is often used to explain and make things easier to understand when any scientific topic needs to be demonstrated and explained.

as in this case where a scientist wants to use a model to present the results of his detailed scientific investigation. he should do it as it will him to make the audience understand the concept in a much better way. also, it can be changed according to new scientific understandings.