g 3.232 g of an unknown solid is dissolved in 363.2 g of benzene. The freezing point of the solution decreases by What is the molar mass of the unknown solid. The freezing point depression constant for benzene is

18.2g/mol is the molar mass of the unknown solid assuming change in freezing point is 2.5°C

Explanation:

In this problem, there is no value of the freezing point depression and the constant for benzene, if:

Freezing point decreases by 2.5°C

And freezing point depression constant for benzene is 5.12°C/m

We can solve the problem as follows:

The freezing point depression is a colligative property that follows the equation:

ΔT = kf*m*ï

Where ΔT is change in temperature (We are assuming is 2.5°C)

Kf is freezing point depression constant for benzene (5.12°C/m)

m is molality of solution (Moles solute / kg solvent)

i is Van't hoff factor (For all solutes dissolved in organic solvents = 1)

Solving for m:

2.5°C = 5.12°C/m*m*1

m = 0.4883m

As molality is defined as moles of solute / kg of solvent and kg of solvent are 0.3632kg:

0.4883m = moles solute / 0.3632kg

0.177 moles of solute

Molar mass is defined as the mass of one mole of substance. Thus, molar mass of an unknown solid is:

3.232g / 0.177 moles of solute =

18.2g/mol is the molar mass of the unknown solid assuming change in freezing point is 2.5°C

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

Idon't know hope someone you