HELP IGNORE IF YOU DON'T KNOW BRAINLIEST!! Commercial vinegar is a 5.00% by mass aqueous solution of ethanoic acid. FIND MOLARITY of ethanoic acid in vinegar. Density of vinegar
is 1.00 g/mL

Molarity of acetic acid in vinegar is given by mole sof aceticacidper litre of the solution.
now here we have,
moles of acetic acid = mass of acetic acid taken/ molecular massofit
now we also know that density = mass/ volume
so the formula of molarity = mass of solute /(molecular mass ofsolute x volume of solution)
= mass of solute / ( molecular mass ofsolutex mass of solution / desnity)
= mass % of vinegar / (molecular massof solute / density)
= (5 /100)/ ( 60/ 1000)
= 5/6
=0.833 (ans)
so the molarity is = 0.833 M

Particle exchange energy though elastic collision , hope this .

Hno3(aq) → h+(aq) + no3−(aq). picture ii best represents the strong acid hno3. strong acids are strong electrolytes