What volume of 18.0 M sulfuric acid must be used to prepare 15.5 L of 0.195 M H2SO4?
none of these
0.336 L
168 mL
O 92.3 mL
226 mL

Volume needed to prepare 18.0 M sulfuric acid = (Option B)

Explanation:

Given,

Therefore,

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Cr(oh)3 -> cr(3+) + 3oh-

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.