Calculate the volume in milliliters of a 1.4M sodium carbonate solution that contains 100.g of sodium carbonate Na2CO3. Round your answer to 2 significant digits.

615ml

Explanation:

Vol(ml) = (gms solute)/[(Molar Answer => Conc)(formula Wt solute))] = (100g)/{(1.4M)(116g/mol)} = 0.615L = 615ml.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.