What is the percent of Li in
Li3N?
(Li = 6.94 amu, N = 14.01 amu)

The percentage by mass of lithium in one mole of Li₃N is approximately 59.78%

Explanation:

The given compound is Li₃N

The atomic mass of lithium, Li = 6.94 amu

The atomic mass of nitrogen, N = 14.01 amu

Therefore by definition, we have;

The mass of one mole of lithium, Li = 6.94 g

The mass of one mole of nitrogen, N = 14.01 g

One molecule of Li₃N contains 3 atoms of lithium, Li and 1 atom of nitrogen, N

The mass of one mole of Li₃N = The molar mass of Li₃N = 3 × The mass of one mole of lithium + The mass of one mole of nitrogen

∴ The mass of one mole of Li₃N = 3 × 6.94 g + 14.01 g = 34.83 g

The percentage by mass of lithium, Li, in one mole of Li₃N = 3×6.94/(34.83) × 100 ≈ 59.78%

The percentage by mass of lithium in one mole of Li₃N ≈ 59.78%.

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