A gas sample has volume 3.00 dm3 at 101 kPa. What will be the volume if the
pressure is reduced to 14.2 kPa?

21.3dm³

Explanation:

Given parameters:

Initial volume of gas = 3dm³

Initial pressure  = 101kPa

Final pressure  = 14.2kPa

Unknown

Final volume  = ?

Solution:

To solve this problem, we use the Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

                P₁ V₁  = P₂ V₂

P and V are pressure and Volume

1 and 2 are the initial and final states

Now insert the parameters and solve;

         101 x 3 = 14.2 x V₂  

                  V₂  = 21.3dm³