An experiment shows that 13.88g of Calcium choride were obtained from the combination of 5g of Ca with chlorine what is the empirical formula of the compound?

CaCl₂

Explanation:

Mass of Calcium chloride  = 13.88g

Mass of Ca = 5g

So,

Mass of chlorine  = 13.88g - 5g  = 8.88g

Now;

Empirical formula of the compound;

 The empirical formula is the simplest formula of a compound;

                                               Elements

                               Ca                                       Cl

Mass                       5                                        8.88

Number of

moles                    5/40                                  8.88/35.5

                             0.125                                   0.25

Divide by

the smallest        0.125/0.125                          0.25/0.125

                                    1                                            2

The empirical formula of the compound is CaCl₂

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.

5.6⋅10−^19  j

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